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Collaborative exploration

\(k\) agents start together at the root of an unknown graph and must visit all its nodes; how much faster than one agent can a team be?

Problem statement and measuresexpand

A team of \(k\) distinguishable agents starts at a node \(s\) (the root) of an unknown connected graph with \(n\) nodes; \(D\) is the largest distance from \(s\). In synchronous rounds every agent traverses at most one edge. When an agent reaches a node it sees the incident edges. The team must visit every node (some papers also require all agents to return to \(s\); the bounds coincide asymptotically).

Time is the number of rounds (in the asynchronous model: the total number of moves). The offline optimum is \(\Theta(n/k + D)\), so an algorithm that explores every tree in \(\mathrm{CR}(k)\cdot(n/k+D)\) rounds is called \(\mathrm{CR}(k)\)-competitive; a single depth-first search is \(O(k)\)-competitive. Memory is bits per agent; most of this literature lets it be unbounded.

Unless a variant says otherwise, nodes are labelled (an agent recognises a node it has seen), which is the standard assumption of collective tree exploration; on trees it does not matter for lower bounds Disser et al. 2020. With anonymous nodes and \(k = n\), the problem is solved by rooted dispersion.

Measures: Time, rounds until every node is visited (asynchronous: total moves); Memory, bits per agent.

Trees, communication by whiteboards only

verified
Time: polynomial gapMemory: unknown

Agents talk only by writing at the node they occupy; the original algorithm still gives \(O(k/\log k)\).

Assumed (added on the last edge are outlined)

+Graph dynamicsstatic graph+Edge directionundirected+Node identifierslabelled nodes (an agent can recognise a node it has visited)+Node memorywhiteboards at nodes+Timingsynchronous rounds+Topologytree

Not assumed

RandomnessdeterministicCommunicationnone (silent agents; only see how many agents are co-located)Team sizeany number \(k\) of agents
Formal definitions of this setting
Graph dynamics: static graph
\(G_t=G\) for all \(t\): the edge set never changes.
Edge direction: undirected
\(G=(V,E)\) with \(E\subseteq\binom V2\); every edge can be traversed in both directions.
Node identifiers: labelled nodes
Each node \(v\) carries a distinct identifier that agents at \(v\) can read; hence an agent can recognise a node it has visited.
Randomness: deterministic
The next state and move of an agent are a function of its current state and what it observes.
Communication: no communication
Agents exchange no messages; an agent at \(v\) observes only the number of agents at \(v\) (and, where stated, whether that number changed).
Node memory: whiteboards
Each node \(v\) has a whiteboard of bounded size that agents at \(v\) can read and write, with mutual exclusion.
Timing: synchronous
Time proceeds in rounds \(t=1,2,\dots\); in every round every agent communicates, computes and moves (at most one edge) simultaneously.
Team size: any \(k\)
Any number \(k\ge 2\) of agents.
Topology: tree
\(G\) is connected and acyclic: \(|E|=n-1\).

What is known

Time · rounds until every node is visited (asynchronous: total moves)
polynomial gap
\(O(k/\log k)\) versus the inherited \(\Omega(\log k/\log\log k)\) competitive ratio.
lower boundnone known
introductory—
current best
\(O(D + n/\log k)\)
Memory · bits per agent
unknown
Memory is not bounded in these papers.
lower boundnone known
introductory—
current best—

Results, in order of publication

Time \(O(D + n/\log k)\)

Introductory and current best in this model.

Open questions

  1. Is there a separation between write-read and complete communication? Cosson & Massoulié 2025 conjecture that centralised communication helps.

What carries over from neighbouring settings

Read off the order of assumptions, not checked case by case: results may carry extra assumptions (shown on their pages), and asynchronous time is measured in epochs.

Algorithms from weaker settings work here

Trees, no communication
Time \(O(k)\cdot\text{optimal}\)
Trees, asynchronous, whiteboards only
Time \(2n+O(k^2 2^k D)\)

Lower bounds from stronger settings hold here

No catalogued stronger setting.

Know a better result for this setting, or found a mistake? Suggest a result · Report an error. Accepted contributions are acknowledged.