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Evacuation

Robots start at the centre of a disk (or a polygon) and must all leave through an exit at an unknown point of the boundary, as fast as possible.

Problem statement and measuresexpand

\(k\) unit-speed robots start together at the centre of a unit disk (or the centroid of a unit equilateral triangle or square). An exit lies at an unknown point of the boundary; a robot recognises it only on reaching it. Time is the worst case, over exit positions, of the time until the last robot reaches the exit (in priority evacuation, where one robot is the queen: until the queen does).

Measures: Evacuation time, worst-case time until the last robot (or the queen) reaches the exit; unit disk, unit speed.

Disk, two wireless robots of different speeds

verified
Evacuation time: polynomial gap

With speeds \(1\) and \(v \ge 1\), two wireless robots evacuate optimally for \(v \ge 2.75\); for smaller \(v\) the bounds are within a factor \(1.22\).

Assumed (added on the last edge are outlined)

+Domainunit disk, start at the centre+Number of robotstwo robots+Communicationwireless: instant communication at any distance+Faultsno faults

Not assumed

Goalevery robot must reach the exitExitsone exitSpeedsrobots may have different maximum speedsRandomnessdeterministic
Formal definitions of this setting
Domain: disk
The unit disk; robots start at its centre; the exit is a point of the boundary circle.
Number of robots: two robots
Two robots.
Goal: all robots
The task ends when the last robot reaches the exit.
Exits: one exit
One exit, at an unknown point of the boundary.
Communication: wireless
Wireless: every robot can send messages to every other robot instantly at any distance.
Faults: no faults
Every robot detects and reports the target.
Speeds: distinct speeds
Each robot \(i\) has its own maximum speed \(v_i\), known to all.
Randomness: deterministic
Trajectories are fixed functions of the information received.

What is known

Evacuation time · worst-case time until the last robot (or the queen) reaches the exit; unit disk, unit speed
polynomial gap
Tight for \(v \ge 2.75\); a constant factor below it.
lower bound
\(\text{matching for } v \ge 2.75\) Lamprou et al. 2020
bottleneckunknown exit
holds when
  • speeds \(1\) and \(v \ge 1\), both known
  • Section 5
introductory—
current best
\(\tfrac{1+2\arccos(-2/v)}{v}+\sqrt{1-4/v^2}\)

Results, in order of publication

Lamprou et al. 2020 current best
Evacuation time \(\tfrac{1+2\arccos(-2/v)}{v}+\sqrt{1-4/v^2}\)

Introductory and current best: optimal (Half-Chord) for \(v \ge 2.75\); for \(1 \le v < 2.75\) the best of three algorithms, within a factor \(1.22\) of the lower bound.

Open questions

  1. Optimal evacuation for \(1 < v < 2.75\), for more than two robots, and face-to-face Lamprou et al. 2020.

Notes

Checked against the full text (arXiv version).

What carries over from neighbouring settings

Read off the order of assumptions, not checked case by case: results may carry extra assumptions (shown on their pages), and asynchronous time is measured in epochs.

Algorithms from weaker settings work here

No catalogued weaker setting.

Lower bounds from stronger settings hold here

Two wireless robots, disk
Evacuation time \(1+2\pi/3+\sqrt{3}\)
Disk, priority evacuation, queen and one servant
Evacuation time \(\approx 4.56798\)

Branches from here

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