Evacuation
Robots start at the centre of a disk (or a polygon) and must all leave through an exit at an unknown point of the boundary, as fast as possible.
Problem statement and measuresexpand
\(k\) unit-speed robots start together at the centre of a unit disk (or the centroid of a unit equilateral triangle or square). An exit lies at an unknown point of the boundary; a robot recognises it only on reaching it. Time is the worst case, over exit positions, of the time until the last robot reaches the exit (in priority evacuation, where one robot is the queen: until the queen does).
Measures: Evacuation time, worst-case time until the last robot (or the queen) reaches the exit; unit disk, unit speed.
Two wireless robots, disk
standard settingverifiedTwo wireless robots evacuate the unit disk in exactly \(1+2\pi/3+\sqrt3 \approx 4.826\).
Assumed (added on the last edge are outlined)
Not assumed
Formal definitions of this setting
- Domain: disk
- The unit disk; robots start at its centre; the exit is a point of the boundary circle.
- Number of robots: two robots
- Two robots.
- Goal: all robots
- The task ends when the last robot reaches the exit.
- Exits: one exit
- One exit, at an unknown point of the boundary.
- Communication: wireless
- Wireless: every robot can send messages to every other robot instantly at any distance.
- Faults: no faults
- Every robot detects and reports the target.
- Speeds: equal speeds
- All robots move at most at unit speed.
- Randomness: deterministic
- Trajectories are fixed functions of the information received.
What is known
- deterministic
- start at the centre
Results, in order of publication
Introductory and current best.
Open questions
None recorded for this variant.
Notes
With one robot that has crashed and must be carried out, see Chauffeuring. In the unit disk of an \(\ell_p\) norm, two wireless robots evacuate optimally for every \(p \ge 1\), in time \(5\) for \(p = 1\) and \(p = \infty\) and about \(4.7544\) at best Georgiou et al. 2023. If every robot must visit every one of \(k\) treasures, \(k = 1\) is this problem Kaminski et al. 2026, a preprint.
What carries over from neighbouring settings
Read off the order of assumptions, not checked case by case: results may carry extra assumptions (shown on their pages), and asynchronous time is measured in epochs.
Algorithms from weaker settings work here
Lower bounds from stronger settings hold here
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