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Evacuation

Robots start at the centre of a disk (or a polygon) and must all leave through an exit at an unknown point of the boundary, as fast as possible.

Problem statement and measuresexpand

\(k\) unit-speed robots start together at the centre of a unit disk (or the centroid of a unit equilateral triangle or square). An exit lies at an unknown point of the boundary; a robot recognises it only on reaching it. Time is the worst case, over exit positions, of the time until the last robot reaches the exit (in priority evacuation, where one robot is the queen: until the queen does).

Measures: Evacuation time, worst-case time until the last robot (or the queen) reaches the exit; unit disk, unit speed.

Line, a sender and a receiver

verified
Evacuation time: tight

A robot that can only send and one that can only receive wirelessly evacuate the line with ratio exactly \(3+2\sqrt2\).

Assumed (added on the last edge are outlined)

+Domainthe infinite line+Number of robotstwo robots+Communicationasymmetric: senders and receivers+Faultsno faults+Speedsall robots have the same unit speed

Not assumed

Goalevery robot must reach the exitExitsone exitRandomnessdeterministic
Formal definitions of this setting
Domain: line
The robots start at the origin of the real line; the exit is at an unknown point at distance at least \(1\); the measure is the competitive ratio, the evacuation time divided by that distance.
Number of robots: two robots
Two robots.
Goal: all robots
The task ends when the last robot reaches the exit.
Exits: one exit
One exit, at an unknown point of the boundary.
Communication: sender/receiver
Sender/receiver: one robot can only transmit and the other only receive, instantly at any distance.
Faults: no faults
Every robot detects and reports the target.
Speeds: equal speeds
All robots move at most at unit speed.
Randomness: deterministic
Trajectories are fixed functions of the information received.

What is known

Evacuation time · worst-case time until the last robot (or the queen) reaches the exit; unit disk, unit speed
tight
Exactly \(3+2\sqrt2\).
lower bound
\(3+2\sqrt2\) Czyzowicz et al. 2021
bottleneckone-way communication
holds when
  • Theorem 10
introductory—
current best
\(3+2\sqrt2\)

Results, in order of publication

Evacuation time \(3+2\sqrt2\)

Introductory and current best (Theorem 1).

Open questions

  1. Close the gaps for one sender and many receivers (\(2+\sqrt5\) against \(5\)) and for many senders and one receiver (\(3\) against about \(5.681\)) Czyzowicz et al. 2021.

Notes

If an extra vehicle (a bike) can carry a robot faster, sender/receiver evacuation on the line has piecewise bounds in the bike's speed Jawhar & Kranakis 2025. Checked against the full text of Czyzowicz et al. 2021.

What carries over from neighbouring settings

Read off the order of assumptions, not checked case by case: results may carry extra assumptions (shown on their pages), and asynchronous time is measured in epochs.

Algorithms from weaker settings work here

Line, two face-to-face robots of different speeds
Evacuation time \(\tfrac{1+3v}{1-v}\ (v \le \tfrac13),\ 9v\ (v \ge \tfrac13)\)

Lower bounds from stronger settings hold here

No catalogued stronger setting.

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