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Evacuation

Robots start at the centre of a disk (or a polygon) and must all leave through an exit at an unknown point of the boundary, as fast as possible.

Problem statement and measuresexpand

\(k\) unit-speed robots start together at the centre of a unit disk (or the centroid of a unit equilateral triangle or square). An exit lies at an unknown point of the boundary; a robot recognises it only on reaching it. Time is the worst case, over exit positions, of the time until the last robot reaches the exit (in priority evacuation, where one robot is the queen: until the queen does).

Measures: Evacuation time, worst-case time until the last robot (or the queen) reaches the exit; unit disk, unit speed.

Triangle, two wireless robots starting on the boundary

verified
Evacuation time: tight

Two wireless robots starting on the boundary of a non-obtuse triangle evacuate in half the perimeter if they may choose their start, which is optimal.

Assumed (added on the last edge are outlined)

+Domainunit equilateral triangle, start at the centroid+Number of robotstwo robots+Communicationwireless: instant communication at any distance+Faultsno faults+Speedsall robots have the same unit speed

Not assumed

Goalevery robot must reach the exitExitsone exitRandomnessdeterministic
Formal definitions of this setting
Domain: triangle
The equilateral triangle of unit side; robots start at its centroid; the exit is a point of the boundary.
Number of robots: two robots
Two robots.
Goal: all robots
The task ends when the last robot reaches the exit.
Exits: one exit
One exit, at an unknown point of the boundary.
Communication: wireless
Wireless: every robot can send messages to every other robot instantly at any distance.
Faults: no faults
Every robot detects and reports the target.
Speeds: equal speeds
All robots move at most at unit speed.
Randomness: deterministic
Trajectories are fixed functions of the information received.

What is known

Evacuation time · worst-case time until the last robot (or the queen) reaches the exit; unit disk, unit speed
tight
When the algorithm chooses the start.
lower bound
\((a+b+c)/2\) Georgiou & Jang 2026
bottleneckunknown exit
holds when
  • Theorem 1
  • non-obtuse triangle with sides \(a \ge b \ge c\)
  • the algorithm chooses the starting edge and point
introductory
\(3/2+y\)
current best
\((a+b+c)/2\)

Results, in order of publication

Evacuation time \(3/2+y\)

Equilateral unit triangle, start on the boundary at distance \(y\) from a side's midpoint; tight; as cited by later papers.

Evacuation time \((a+b+c)/2\)

Non-obtuse triangles (Theorem 1); separate tight or near-tight bounds when the adversary chooses the edge or the point.

Open questions

  1. Face-to-face evacuation of general triangles, and wireless evacuation of obtuse triangles Georgiou & Jang 2026.

Notes

With many wireless robots an equilateral triangle is evacuated in \(1+\sqrt3/3\), optimal with 6 robots Czyzowicz et al. 2015; with communication range \(r\), \(6+2\lceil 1/r-1\rceil\) robots achieve it Bagheri et al. 2019. Checked against the full texts of Georgiou & Jang 2026 and Bagheri et al. 2019.

What carries over from neighbouring settings

Read off the order of assumptions, not checked case by case: results may carry extra assumptions (shown on their pages), and asynchronous time is measured in epochs.

Algorithms from weaker settings work here

Lower bounds from stronger settings hold here

No catalogued stronger setting.

Know a better result for this setting, or found a mistake? Suggest a result · Report an error. Accepted contributions are acknowledged.