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Graph exploration by a single agent

One agent starts at a node of an unknown anonymous graph and must visit every node; how much memory does it need, which pebbles or knowledge make it possible, and how fast can it be?

Problem statement and measuresexpand

A single deterministic agent is placed at a node \(s\) of a connected graph \(G\) with \(n\) nodes, \(m\) edges and maximum degree \(\Delta\). Nodes are anonymous (they carry no names the agent can read), and the edges at each node are numbered locally; these numbers are the node's ports. The agent sees the degree of its node and the port by which it entered. It must visit every node of \(G\). Three termination requirements are standard:

  • perpetual exploration: every node is eventually visited; the agent never has to stop;
  • exploration with stop: every node is visited and the agent then stops, anywhere;
  • exploration with return: every node is visited and the agent stops at \(s\).

Return implies stop, and stop implies perpetual exploration. Memory is the number of bits of the agent's state; when the agent carries pebbles (objects it can drop on a node and pick up again) their number is reported with the memory. Time is the number of moves (edge traversals) until exploration is complete; for periodic exploration it is the period. Unless a variant says otherwise the agent knows nothing about \(G\), not even \(n\).

Exploration is the oldest problem of the mobile-agent literature: it started as maze search by finite automata, and the question of how little memory suffices runs from Budach's impossibility (1978) to Reingold's log-space algorithm (2005). Several agents exploring together form the sibling problem, collaborative exploration.

Measures: Time, edge traversals until every node is visited (for periodic exploration: the period); Memory, bits of agent memory; pebbles, if any, are counted separately.

Randomized exploration when \(n\) is known

verified
Time: unknownMemory: unknown

A random walk covers any graph in expected \(2m(n-1)\) steps; with a step counter and a bound on \(n\) it stops after exploring with good probability.

Assumed (added on the last edge are outlined)

+Graph dynamicsstatic graph+Edge directionundirected+Knowledgean upper bound on \(n\) is known+Randomnessrandomized (agents have private coins)+Termination requirementexplore, then stop anywhere

Not assumed

Node identifiersanonymous nodesMarkersno markersPreprocessingports and nodes as given by an adversaryTopologyarbitrary connected graph
Formal definitions of this setting
Graph dynamics: static graph
\(G_t=G\) for all \(t\): the edge set never changes.
Edge direction: undirected
\(G=(V,E)\) with \(E\subseteq\binom V2\); every edge can be traversed in both directions.
Node identifiers: anonymous nodes
Nodes have no identifiers; an agent at \(v\) sees only \(\deg(v)\) and the port numbers \(1,\dots,\deg(v)\), which are assigned locally and independently at each endpoint of an edge.
Knowledge: knows a bound on \(n\)
The agent is given an integer \(N\ge n\) (an upper bound on the number of nodes) as input.
Randomness: private coins
Each agent additionally has access to independent fair coin flips; guarantees hold with probability 1, in expectation, or with high probability, as stated per result.
Markers: no markers
The agent cannot mark nodes.
Preprocessing: adversarial ports
Port numbers (and any node labels) are chosen by an adversary.
Termination requirement: with stop
The agent visits every node and then halts, at any node. Also called terminating exploration.
Topology: any topology
\(G\) is any connected graph in the class allowed by the other axes.

What is known

Time · edge traversals until every node is visited (for periodic exploration: the period)
unknown
No lower bound recorded for randomized agents.
lower boundnone known
introductory—
current best
\(O(mn)\)
expected timestops correctly with constant probability (Monte Carlo)
Memory · bits of agent memory; pebbles, if any, are counted separately
unknown
No lower bound recorded for randomized agents.
lower boundnone known
introductory—
current best
\(O(\log n)\)
expected timestops correctly with constant probability (Monte Carlo)

Results, in order of publication

Time \(O(mn)\)Memory \(O(\log n)\)
expected timestops correctly with constant probability (Monte Carlo)

Expected cover time at most \(2m(n-1)\) from any start (Theorem 4). Running the walk for a multiple of that many steps with an \(O(\log n)\)-bit counter gives the Monte Carlo agent.

Open questions

  1. What is the memory needed by a randomized agent that must stop correctly with high probability, as a function of \(n\)?

Notes

The same paper proves by the probabilistic method that universal traversal sequences of length \(O(n^3\log n)\) exist for connected \(\Delta\)-regular graphs, the constant depending on \(\Delta\) (the proof uses length \(2\Delta n(n-1)(\Delta n+2)\lceil\log n\rceil\)) Aleliunas et al. 1979. For directed graphs the cover time can be exponential, while Eulerian digraphs behave like undirected graphs Aleliunas et al. 1979; Reingold later constructed universal exploration sequences in log space Reingold 2008.

What carries over from neighbouring settings

Read off the order of assumptions, not checked case by case: results may carry extra assumptions (shown on their pages), and asynchronous time is measured in epochs.

Algorithms from weaker settings work here

Exploration with stop when \(n\) is known
Time \(n^{O(1)}\)Memory \(O(\log n)\)

Lower bounds from stronger settings hold here

No catalogued stronger setting.

Know a better result for this setting, or found a mistake? Suggest a result · Report an error. Accepted contributions are acknowledged.